18k^2+45k-63=0

Solution for 18k^2+45k-63=0 equation:

18k^2+45k-63=0

a = 18; b = 45; c = -63;
Δ = b2-4ac
Δ = 452-4·18·(-63)
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-81}{2*18}=\frac{-126}{36}
=-3+1/2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+81}{2*18}=\frac{36}{36}
=1
$